Hvap = + 44.0 kJ/mole
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Chemistry, 01.05.2021 01:00 jasminemarie610
Given that the enthalpy of vaporization for water is:
H2O(1) ►H2O(g)
Hvap = + 44.0 kJ/mole
Calculate H for each of the following processes:
a. Evaporating 3.00 moles of water
b. Evaporating 3.00 grams of water
c. Condensing 20.0 grams of water
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Answers: 2
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You know the right answer?
Given that the enthalpy of vaporization for water is:
H2O(1) ►H2O(g)
Hvap = + 44.0 kJ/mole
Hvap = + 44.0 kJ/mole
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