Examine the sets of bonds given in the choices. which one arranges the bonds in order of increasing (shortest to longest) bond length? examine the sets of bonds given in the choices. which one arranges the bonds in order of increasing (shortest to longest) bond length? c—cl, c—f, c—br, c—i c—i, c—br, c—cl, c—f c—f, c—cl, c—i, c—br c—f, c—cl, c—br, c—i

The stronger the pull of the element towards each other, the shorter is the bond length, and vice versa. The cause of this pull is the difference of their electronegativities. This is the ability of the element to attract electrons toward itself. In periodic trends, electronegativity increases from left to right, and from bottom to top. Thus, the arrangement of most electronegative to least electronegative element is: Cl > Br > I. Consequently, the arrangement of the shortest to longest bond length is: C-Cl > C-Br > C-I.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

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