Chemistry, 29.04.2021 01:00 2Pallie2

An equilibrium mixture at 425°C is found to consist of 0.00183 mol/L of H2, 0.00313 mol/L of 12, and 0.0177 mol/L of HI. Write the equilibrium expression and solve for Keq for the
reaction H2(g) + 12(g) + 2HI(g).

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An equilibrium mixture at 425°C is found to consist of 0.00183 mol/L of H2, 0.00313 mol/L of 12, a...

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An equilibrium mixture at 425°C is found to consist of 0.00183 mol/L of H2, 0.00313 mol/L of 12, and 0.0177 mol/L of HI. Write the equilibrium expression and solve for Keq for the reaction H2(g) + 12(g) + 2HI(g).

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Another question on Chemistry

An equilibrium mixture at 425°C is found to consist of 0.00183 mol/L of H2, 0.00313 mol/L of 12, and 0.0177 mol/L of HI. Write the equilibrium expression and solve for Keq for the
reaction H2(g) + 12(g) + 2HI(g).