Using the formula (Q =MCvT), perform the calculations below. 3.100g of water at 4*C is heated to 29*C. If the specific heat of water is 4.18j/g*C.
Calculate the amount of energy needed. Hint find the change in temperature before solve!
Q= M c v T. m= mass (g), c = heat capacity, v T = change in temp (T f-Ti) .
Q= (100).(4.18).(29*C- 4.0*C)

what's the

the answer is 1 i believe

confused

confused             hewdejdnjnjsnd

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.