9.49.8 grams of Kl is dissolved in 1.00 kg of solvent. What is the molality?

Molality = 9.498 mol  k g − 1

Explanation:

A final way to express the concentration of a solution is by its molality. The molality ( m ) of a solution is the moles of solute divided by the kilograms of solvent. A solution that contains 1.0 mol of NaCl dissolved into 1.0 kg of water is a “one-molal” solution of sodium chloride.

molality = number of moles of solute/ mass of solvent in kg

number of moles of KI = mass of KI / molar mass of KI  

number of moles of KI = 9.49.8 g / 1.00 g  m o l − 1

number of moles of KI = 9.498 moles  

molality = 9.498 moles / 1kg  

molality = 9.498 mol  k g − 1

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explanation:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2