Para la combustión del etano, C2 H6 , calcule : a) La masa en gramos de Oxígeno para que reaccionen con 425 ml de etano en condiciones STP
b) El volumen de dióxido de Carbono medido a 20.0 °C y 750 torr que pueden producirse a partir de 3.75 moles de Oxígeno.
PA:
C= 12.0 ; H= 1.0 ; O= 16.0

For the combustion of ethane, C2 H6, calculate:
a) The mass in grams of Oxygen to react with 425 ml of ethane under STP conditions
b) The volume of Carbon dioxide measured at 20.0 ° C and 750 torr that can be produced from 3.75 moles of Oxygen.

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence