A 5.00 L sample is at STP conditions. What pressure will the air exert if the temperature is increased to 127 °C and the air is allowed to expand to 25.0 L ? a.7.33 atm
b.0.293 atm
c.0.137 atm
d.2.15 atm

If a container has 13.0 moles of a gas being held at a pressure of 3.40 atm and a temperature of 225.0 K, how many liters of gas are present?
a.70.6 L
b.53.7L
c.7149L
d.1.42x10^-2L

58750.08068 is the answer i think

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2