Calculate the volume that 8.81 grams of carbon monoxide gas (CO) at standard temperature and pressure (STP) will occupy. (22.4 L/mol)

All ideal gases occupy 22.4 L/mol at STP. To determine the volume this one will occupy you need to know how many mols of CO is in 8.81g of CO. So, you should should:

1) Convert 8.81g to mols.

2) To do this you need to calculate the molar mass of CO

3) This is calculated by using the masses of each element from the periodic table (https://ptable.com/#Properties)

4) The table tells us that 1 mol of C is 12g and that 1mol of O is 16g. So, you can determine the mass of 1 mol of CO. Lets say 1mol of CO has a mass of 20g (it doesn't).

5) Once you have that you say " if 1mol = 20g, then x mols = 8.81g) and solve the ratio.

6) This will tell you how many mols of CO you have.

7) Once you know that you say "since 1 mol of an ideal gas takes up 22.4L, then how many liters will my gas takes up if i have x mols of this gas"

And voila!

HINT: I think the answer might be between 1 - 10 L. :):)