A chemist wishes to prepare 148.00 mL of acetic acid/sodium acetate buffer solution with a pH of 5.29 and a total concentration of the components equal to 0.47 M. The pKa for acetic acid is 4.75. What mass of acetic acid (molar mass 60.05 g/mol) is required?
What mass of sodium acetate (molar mass 82.03 g/mol) is required?

the answer is alpha particles hope i you

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2