What is the ratio of the volume of oxygen gas to the volume of water vapor in the following reaction?

The ratio of volumes in the given case illustrates the Gay Lussac's Law of Gaseous Volumes.

- The law was given by the french chemist Gay Lussac in the year 1806.

- He stated that when gases are combined or are produced in a chemical reaction, they do so in a simple ratio by volume.

- It is given that 2 volumes of hydrogen combine with 1 volume of oxygen producing 2 volumes of water.

- This is in accordance with this law.

Explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.