Calculate the pH for a 1.0 x 10-5 M solution of OH at 25°C. pH = -log[H*), pOH = -log[OH-]
14 = pH + POH
0 pH = 11.00
0 pH = 9.00
0 pH = 6.00
0 pH = 3.00

The following reaction shows the products when sulfuric acid and aluminum hydroxide react. al(oh)3 + h2so4 → al2(so4)3 + h2o the table shows the calculated amounts of reactants and products when the reaction was conducted in a laboratory. sulfuric acid aluminum hydroxide initial amount of reactant 40 g 15 g theoretical yield of water from reactant 14.69 g 10.38 g what is the approximate amount of the leftover reactant? 11.73 g of sulfuric acid 10.33 g of sulfuric acid 11.12 g of aluminum hydroxide 13.67 g of aluminum hydroxide

Define dew point. i am writing this part to be able to ask the question

In pqr m< p=60 m< q= 30 and m