My sporty mini van needs 19,126 kJ of energy in order to pass a fast moving street sweeper on the road. Using the following equation, determine how many grams of gasoline (C8H18) will be used up in order to make this happen. 2 C8H18 + 25 O2 --> 16 CO2 + 18 H2O \DeltaΔH = -10,990 kJ

3 1/4 %

explanation:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally