) A rigid tank initially contains 5 kg nitrogen (N2) at 500 kPa and 327 oC. N2 is gradually cooled to 27 oC. due to the heat loss from N2 to ambient air at 20 oC, which is considered as boundary temperature of heat transfer. (5a). (4p) Please calculate the change in the total entropy of N2 during this cooling process (5b). (3p) Please find the heat loss from tank to ambient air during this process. (5c). (3p) Please determine the entropy generation during this process. (5d). (2p) Is this process reversible, irreversible or impossible

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied