Chemistry, 21.04.2021 01:20 navarretteisaiah09
you are to compare two different processes. In the first process, 5molis of n-butane gas enters the unit at 400 °C and 1000 kPa and exits at 364.5 °C and 225.2 kPa. An energy balance across this unit process reveals that the heat flow around the unit is Q = -29,856 W and no shaft work is produced. The specific change of entropy for the gas as it goes through the unit is 3.1491 Nmol•K). The second process has exactly the same inlet and outlet conditions (5molis of n-butane gas enters the unit at 400 °C and 1000 kPa and exits at 364.5 °C and 225.2 kPa), but it operates adiabatically producing shaft work. The temperature of the surroundings for both units is 25°C. There is no change of potential or kinetic energy in either process. a. Determine the shaft work (W) and the specific change of entropy (J/(mol. K)) for the gas for the second process. b. Determine the lost work (W) for the two processes. c. Calculate the ideal work (W)for the two processes. d. Are the processes thermodynamically feasibly? Why?
Answers: 1
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you are to compare two different processes. In the first process, 5molis of n-butane gas enters the...
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