A steel ornament has a mass of 0.0785 kg and changes from a temperature of 15.0∘C to 32.3∘C. How much heat energy did it gain? The specific heat of this type of steel is 470 J/kg∘C.

The answer is b because c don't explain why the moths are on them and it isn't a because as we know only one species of moth does this

Depends on the speed of the car.

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

Answeropposite;