Answers: 1
![\frac{[A^-]}{[HA]}=1](/tpl/images/0276/4567/47142.png)
![\frac{[A^-]}{[HA]}=\frac{Ka}{[H^+]}](/tpl/images/0276/4567/698ec.png)
![[H^+]=10^{-pH}=10^{-3.75}=1.78x10^{-4}M](/tpl/images/0276/4567/512f1.png)
![\frac{[A^-]}{[HA]}=\frac{1.78x10^{-4}}{1.78x10^{-4}}\\\frac{[A^-]}{[HA]}=1](/tpl/images/0276/4567/ab95a.png)
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What is the ratio of [a–]/[ha] at ph 3.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?...
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