Asaturated solution of nano3 is prepared at 60.°c using 100. grams of water. as this solution is cooled to 10.°c, nano3 precipitates (settles)
out of the solution. the resulting solution is saturated. approximately how many grams of nano3 settled out of the original solution?
(1) 46 g (3) 85 g
(2) 61 g (4) 126 g

The answer is 46 g

The explanation :

According to the attached curve of the relation between the temperature and the grams in solutions:

-we can see from the curve that the grams of NaNO3 at 60°C = 126 g

-and the grams of NaNO3 at 10°C = 80 g

-so, To get the grams of NaNO3 settled out of the original solution, we will subtract the grams of NaNO3 at 10°C - the grams of NaNO3 at 60°C

126 g - 80 g = 46 g

∴ the correct answer is 46 g