What mass of melamine, c3n3(nh2)3, will be obtained from 113.0 kg of urea, co(nh2)2, if the yield of the overall reaction is 73.0 % ?

The balanced equation for the reaction is:

6 HNCO(l) → C3N3(NH2)3(l) + 3 CO2(g)

Convert amount of urea from kg to moles

Molar Mass of urea = 60.06 g/mol so, 113 kg urea contains

113 kg / 60.06 = 1.88 mol urea

From balanced equation 6 moles of urea yields only 1 melamine, so divide the moles of urea by 6. 

1.88 / 6 = 0.313 kmol melamine

Now multiply 0.313 with molar mass of melamine that is 126 g/mol

126 x 0.313 = 39.438 kg

Yield of overall reaction is 73% so multiply 39.438 with 0.73

39.438 x 0.73 = 28.799 kg is the answer

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