Achloride of silicon contains 79.1 mass % cl. (a) what is the empirical formula of the chloride?

SiCl₃

Explanation:

To solve this problem, let's assume that we have 100 g of that chloride of silicon. We then would have 79.1 g of Cl and 100 - 79.1=20.9 g of Si.

Then we calculate the amount of moles in the mass of each element, using the elements' atomic weight:

Now we divide the number of moles by the lowest number, in this case, it's the moles of Si:

2.2313 / 0.7443 = 2.9978 => 3

0.7443 / 0.7443 = 1

Thus the empirical formula is SiCl₃

where's the diagram?

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."