Calculate the amount (in grams) of kcl present in 75.0 ml of 2.10 m kcl

V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?

C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol

mKCl: 39+35.5 = 74,5 g/mol

74,5g 1 mol
Xg 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl

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If a hydrogen atom is neutral, it must also have  one electron. an oxygen atom (o) has an atomic number of eight (8). this means a neutral oxygen atom has eight protons and eight electrons. the element actium (ac) has an atomic number of 89, so it has 89 protons and 89 electrons in a neutral atom