Gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 21. g of ethane is mixed with 110. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to 2 significant digits.

The chemical reaction for this is:

2 C2H6 + 7 O2 => 4 CO2 + 6 H2O

Solving for CO2 with each reactant will give:

21.0 g C2H6 x (1 mol C2H6/30.08 g C2H6) x (6 mol H2O/2 mol C2H6) x (18 g H2O/1 mol H2O) = 37.70 g H2O

110 g O2 x (1 mol O2/32.00 g O2) x (6 mol CO2/7 mol O2) x (18 g H2O/1 mol H2O) = 53.04 g H2O

Since the amount of H2O in C2H6 is lower therefore C2H6 is the limiting reactant and the maximum amount of water is only 38 g H2O (2 significant digits)

ANswer:

38 g water

particle   p is an electron and particle q is a neutron