Chemistry, 01.09.2019 05:30 hcameron65

Aslow jogger runs a mile in 13 minutes. calculate the speed in (a) in/s, (b) m/min, (c) km/h. (1 mi= 1609m; 1in=2.54cm)

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Before starting the solution, let's first convert the units to the ones we need:
1- For the distance:1 mile = 1609 meter
= 1609 x 100 = 160900 cm
= 1609 / 1000 = 1.609 km
= (160900 x 1 ) / 2.54 = 63346.45 in
2- For the time:13 minutes = 13 / 60 = 0.2166 hours
= 13 x 60 = 780 seconds

Now, let's start solving:
velocity is calculated using the following rule:
velocity = distance / time

(a) in/seconds
velocity = 63346.45 in / 780 sec = 81.213 in / sec

(b) m/min
velocity = 1609 m / 13 min = 123.769 m/min

(c) km/hr
velocity = 1.609 km / 0.2166 hr = 7.428 km/hr

Answer from: daijahamaker062816

The speed of the Jogger with regards to varying units :

a) 81.21 in/s

b) 123.77 m/min

c) 7.43 km/h

Given data :

Time = 13 minutes = 0.2166 hour = 780 secs

Distance covered = 1 mile = 1609 meters = 160900cm = 1.609 km = 63346.45 inches

Determine the speed of the jogger using the equation below

Speed = distance covered / time

a) Speed in ( in/secs )

= 63346.45 inches / 780 secs

= 81.21 in/s

b) Speed in ( m/min )

= 1609 meters / 13 minutes

= 123.77 m/min

c) Speed in ( km/h )

= 1.609 km / 0.2166 hour

= 7.43 km/h

Hence In conclusion The speed of the Jogger with regards with varying units : 81.21 in/s, 123.77 m/min, 7.43 km/h.

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Aslow jogger runs a mile in 13 minutes. calculate the speed in (a) in/s, (b) m/min, (c) km/h. (1 mi=...

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