Write reaction showing how each of the buffers would neutralize added naoh. hcho2 and nacho2

The acid-base neutralization reaction between formic acid (HCHO2) and sodium hydroxide (NaOH) is

HCHO2(aq) + NaOH(s) --> NaCHO2(aq) + H2O(l)

Formic acid is a weak acid. So, the salt formed here is a basic salt, NaCHO2 or Sodium Formate. A buffer solution is when the system contains either a weak acid and its conjugate strong base or a weak base and its conjugate strong acid. In this case, formic acid is the weak base, while sodium formate is the conjugate strong base. So, this is a buffer system. By definition, a buffer resists pH changes with small addition of either a base or an acid. So, when NaOH is added, it would produce more of sodium formate. As long as formic acid is not depleted, the buffer system would be stable.

D)can be increased in a closed system

30litre of li2o is 1.0002mole approximately 1 mole