How many phosphorus atoms are contained in 158 kg of phosphorus? how many phosphorus atoms are contained in 158 kg of phosphorus? 3.07 × 1027 phosphorus atoms 2.95 × 1027 phosphorus atoms 1.18 × 1024 phosphorus atoms 3.25 × 1028 phosphorus atoms 8.47 × 1024 phosphorus atoms?

To determine the number of phosphorus atoms from a given mass, we need to determine the number of moles of the substance by dividing the molar mass which for in this case is equal to 123.88 g/mol for P4. Then, we multiply Avogadro's number. It represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole.

mole P4 = 158 kg P4 ( 1000 g / 1 kg ) ( 1 mol / 123.88 g ) = 1275.43 mol P4
# of P4 atoms = 1275.43 mol P4 ( 6.022 x 10^23 atoms P4 / 1 mol P4 ) = 7.68x10^26 atoms P4

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