In a certain experiment 1.00 g of sodium bicarbonate and 1.00 g of citric acid are allowed to react. (a) which is the limiting reactant? (b) how many grams of carbon dioxide form? (c) how many

a) Citric acid is the limiting reactant.

b) 0.45804 grams of carbon dioxide formed.

Explanation:

a) Moles of sodium bicarbonate  :

According to reaction,2 moles sodium bicarbonate reacts with 1 mole of citric acid.

Then 0.01190 moles of sodium bicarbonate will react with:

of citric acid

Moles of citric acid :

According to reaction, 1 moles of citric acid reacts with 2 moles sodium bicarbonate.

Then 0.005205 moles of citric acid will react with:

of sodium bicarbonate.

Citric acid is the limiting reactant.

b) Since, citric acid is in limiting amount, amount of carbon dioxide produce  will depend upon on citric acid .

According to reaction , 1 mole of citrc acid gives 2 moles of carbon dioxide.

Then 0.005205 moles of citric acid will give:

of carbon dioxide

Mass of 0.01041 moles of carbon dioxide:

0.01041 mol × 44 g/mol= 0.45804 g

0.45804 grams of carbon dioxide formed.