Write balanced chemical equation for the oxidation of fe2+(aq) by s2o2−6 (aq).

To write a balanced chemical equation for the given redox reaction, we need to know the half reactions of the substances involved. Redox reaction means oxidation-reduction reaction. Oxidation is when one loses electrons making it more positive while reduction is gaining electrons which makes it more negative. Iron here is being oxidized and will have the half reaction:

Fe2+(aq) ---> Fe3+(aq) + e+

 S2O2−6 is being reduced in the process and will have a half reaction of:

S2O2-6 + 4H+ + 2e- > 2H2SO3

Adding the two half reactions would yield to the balanced chemical equation. We do as follows:

2 (Fe2+ ---> Fe3+ + e+)
S2O2-6 + 4H+ + 2e- > 2H2SO3

2Fe2+ + S2O2-6 + 4H+  > 2Fe3+ + 2H2SO3  ( balanced oxidation - reduction reaction )

So what you would do is go through and add 3 teaspoons(tsp) 6 times because of the 6 tablespoons(tbsp). which will give you an answer of 18. another way is to multiply 3x6=18.