Calculate the molality of a solution formed by dissolving 34.8 g of lii in 500.0 ml of water. calculate the molality of a solution formed by dissolving 34.8 g of lii in 500.0 ml of water. 0.520 m 0.260 m 0.254 m 0.696 m 0.130 m

First step is to find the number of moles in 34.8 gm of LiI:
From the periodic table: molar mass of Li = 6.941 while that of I = 126.9
Molar mass of LiI = 6.941 + 126.9 = 133.841
Number of moles = mass/molar mass = 34.8/133.841 = 0.26 moles

Second step is to calculate the molality:
molality = number of moles of solute / kilogram of solvent
At STP: 1L of water = 1Kg, thus, 500 ml of water = 0.5 kg
molality = 0.26/0.5 = 0.52 mole/Kg

The net force is 100

The answer is c. risk