At what temperature would 0.500 moles of gas particles stored in a 100.0 ml container reach a pressure of 15.0 atm?
a) 36500 k
b) 7.96 k
c) 36.5 k
d) 3.60 k

Hey there!

In this case, the equation of Clapeyron is used :

R = 0.082 

Volume in liters :

100.0 mL / 1000 => 0.1 L 

P * V = n * R * T

15.0 * 0.1 = 0.500 * 0.082 * T

1.5 = 0.041 * T

T = 1.5 / 0.041

T = 36.5 K

Answer C