Type in the correct values to correctly represent the valence electron configuration of oxygen: asb2pc
a =
b =
c =

The correct number of valance electrons in the electronic configuration of Oxygen is:

A=2, B=2, and C=4

Explanation:

The atomic number of oxygen is 8

The electronic configuration will be,

The electrons present in the outermost shell is called valence electrons.

Hence, in the second shell, the s-orbital contains 2 electrons and the p-orbital contains 4 electrons.

If all the electrons in the outermost shell are removed the first shell becomes a valance shell where 2 electrons are present in the s-orbital.

Therefore correct valence electron configuration is 2,2,4.

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A=2,  B=2 and  C=4

Explanation: Oxygen is the element with atomic number 8 and thus contains 8 electrons which are filled in order of increasing energy levels.

The valence electrons are electrons which are present in the valence shell i.e. the last shell. Thus the valence electrons of Oxygen are in shell 2 in which s orbital contains two electrons and the p orbital contains 4 electrons.

Thus A= 2, B=2 and C=4.

gas

explanation:

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the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3