What is the molarity of a 1.50 l solution containing 14 g of hcl

Hey there !

Molar mass HCl = 1 + 35.5 => 36.5 g/mol

* Number of moles :

n = m / mm

n = 14 / 36.5

n = 0.383 moles of HCl

Therefore :

M = n / V

M = 0.383 / 1.50

 = 0.255 M

hope this helps!

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

Show an image of the data (˵¯͒ བ¯͒˵)