Calcium chloride (cacl2) is an ionic compound that dissociates in water. a chemist forms a solution by mixing 0.50 mol cacl2 and 1.0 kg of water. how many moles of ions are in the solution?

Calcium chloride (CaCl2) is a salt which dissociates when dissolved in water. Assuming that the dissociation is complete (100 %), then the half reaction for this would be:

CaCl2 ---> Ca2+  +  2 Cl-

We can see that in 1 mole of CaCl2 salt, 1 mole of Ca2+ ion and 2 moles of Cl- ion is created. Therefore there are 3 moles of ion per 1 mole of CaCl2. Using this ratio, the total number of moles of ions in the solution is:

Total number of ions = 0.5 mol CaCl2 * (3 moles ion / 1 mol CaCl2)

Total number of ions = 1.5 moles ion

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml