Agas occupies a 16-liter balloon under a pressure of 1.2 atm. what would the new volume of the balloon be if the pressure were increased to 3.6 atm?

The new volume shall be 5.33 liter

Explanation:

First thing's first, we bring out the parameters mentioned in the question.

We have;

Initial Volume (V1) = 16L

Initial pressure (P1) = 1.2 atm

Final Volume (V2) = ?

Final Pressure (P2) = 3.6atm

Upon looking at the parametwes, we can deduce that we would apply the boyles law because it is the law that relates both parameters (Volume and Pressure).

Boyles's law states that the volume of a fixed mass of gas is inversely proportional to the pressure provided temperature reamins contant.

The mathematical representation is given as;

P1V1 = P2V2

Making V2 subject of interest, we have;

V2 = P1V1 / P2

V2 = (1.2 * 16) / 3.6

V2 = 19.2 / 3.6

V2 = 5.33L

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.