What mass of manganese(ii) chloride must react with sulfuric acid to release 48.5 ml of hydrogen chloride gas at stp? mncl2(s)+h2so4(aq)→mnso4(aq)+2hcl(g )

Note that one mole of any gas at STP occupies 22.4 L of volume. We may use this to calculate the moles of hydrogen chloride gas that need to be produced. This is:
0.0485 / 22.4
0.002 mol

Next, we see that the molar ratio between manganese chloride and hydrogen chloride in the equation is:
1 : 2

So the moles of manganese chloride reacting will be:
0.002 / 2 = 0.001 mol

The molecular mass of manganese chloride is 126 g/mol. The mass reacting will be:
0.001 * 126

0.126 grams of manganese (II) chloride will react. 

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