An electron in the n=6 level of the hydrogen atom relaxes to a lower energy level, emitting light of ? =93.8nm. find the principal level to which the electron relaxed.

We can find the principal level or lower level using Rydberg's formula:

1/w = R(1/L² - 1/U²) 

where:

w is the wavelength (93.8 nm),

L is the lower energy level (unknown)

U the upper energy level (n= 6)

R is Rydberg's constant (10,967,758 waves per meter)

Substituing known values into the equation:
1/(9.38 * 10^-8 m.) = 10,967,758(1/L² - 1-36)

Using the solver function of the calculator to get for L:

L = 0.999 
so L = 1. 
The lower level is 1 (the ground state).

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.