When 4.0 mol h2o react with 4.0 mol al in the reaction below, 2.7 mol of al are used up in the reaction. how many moles of al are left over unreacted?

2 al + 3 h2o → al2o3 + 3h2 (c? )

2.7 mol al left over

2.0 mol al left over

1.3 mol al left over

0.7 mol al left over

Answer : The moles of Al left over unreacted are, 1.3 mole

Explanation : Given,

The total moles of Al are taken in this reaction = 4.0 mole

The moles of Al used in this reaction = 2.7 mole

Now we have to calculate the moles of Al are left over unreacted.

The moles of Al are left over unreacted = The total moles are taken in this reaction - The moles of Al used in this reaction

The moles of Al are left over unreacted = 4.0 mole - 2.7 mole = 1.3 mole

Therefore, the moles of Al left over unreacted are, 1.3 mole

може ли да зареждате повече информация, моля

it's c (engineer's do their work with mechanical stuff not on any living being)