How many moles of sulfuric acid are needed to produce 57.8 milliliters of water? water has the density of 0.987 g/ml. show all steps of your calculation as well as the final answer.

naoh + h2so4 → na2so4 + h2o
my
balance the equation: 2naoh + h2so4 = na2so4 + 2h2o
mass of water = 57.8 ml x 1 g/ml = 57.8g
moles of water= 57.8g/ 18.01 g/mol = 3.21
the ratio between h2so4 and h2o is 1: 2
moles of h2so4 required = 3.21/2 = 1.61