Given that the molar mass of nano3 is 85.00 g/mol, what mass of nano3 is needed to make 4.50 l of a 1.50 m nano3 solution? use .

The molar mass of NaNO3 is 85.00 g/mol and if the 4.50 liter of 1.5 M (if this means moles) then the mass of NaNO3 should just be 85.0 x 1.5 = 127.5grams This appears to be the case since the concentration of the solution is already given at 1.5 moles if M = moles. 

What’s the solution?