Given the following reactions and subsequent ∆h values what is the ∆h for the reaction below?
zn(s) + 1/8s8(s) + 2o2(g) → znso4(s)

given:
zn(s) + 1/8s8(s) → zns(s)
∆h = -183.92kj

2zns(s) + 3o2(g) → 2zno(s) + 2so2(g)
∆h = -927.54kj

2so2(g) + o2(g) → 2so3(g)
∆h = -196.04kj

zno(s) + so3(g) → znso4(s)
∆h = -230.32kj

answers options:
a) 244.01 kj
b) 488.02 kj
c) -488.02 kj
d) -976.03 kj
e) 976.03 kj

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.