What does it mean for a strong base to be in equilibrium?
the position of equilibrium lies far to the right, with products being favored.
the position of equilibrium lies far to the left, with products being favored.
there is a great deal of base and very few ions.
there is an equal amount of reactants and products.

(b is wrong)

The answer is the position of equilibrium lies far to the right, with products being favored.
The dissociation of a base may be written as:
AB ↔ A⁺ + B⁻

If the base is strong, it will dissociate into ions completely. This means that the equilibrium constant for the forward reaction will be greater than that for the backward reaction, and the equilibrium position is far to the right.

It is 4.92 e-4 sorry if i am wrong