How many grams of magnesium metal will react completely with 6.3 liters of 4.5 m hcl? show all of the work needed to solve this problem. mg (s) + 2hcl (aq) yields mgcl2 (aq) + h2 (g)

The reaction is: Mg + 2HCl > MgCl2 + H2 

M = mol / L 
mol = M x L = 4.5 mol/L x 6.3 L = 28.4 mol HCl 
1 mol Mg reacts with 2 mol HCl 
28.4 mol HCl x (1 mol Mg / 2 mol HCl) = 14.2 mol Mg 
Molar mass of Mg is 24.3 g/mol. 
14.2 mol Mg x (24.3 g / 1 mol) = 344 g Mg

The answer is probably c. xylem