If the molar concentration of sodium sulfate (na2so4) is 0.10 m, what is the concentration of sodium ion

Answer : The concentration of sodium ions in a solution is 0.20 M

Explanation :

The dissociation reaction of in solution will be:

From the reaction we conclude that, 1 mole of dissociate in solution to give 2 moles of ion (sodium ion) and 1 mole of ion (sulfate ion).

As per question,

0.10 M of dissociate in solution to give of ion (sodium ion) and 0.10 M of ion (sulfate ion).

Hence, the concentration of sodium ions in a solution is 0.20 M

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.