Given the following chemical reaction: 2 o2 + ch4 co2 + 2 h2o what mass of oxygen is required to completely react with 20 grams of ch4? 6 c 12.01 carbon 1 h 1.01 hydrogen 8 o 16.00 oxygen a. 10 grams o2 b. 20 grams o2 c. 80 grams o2 d. 144 grams o2

The chemical equation is:
CH₄ + 2O₂ → CO₂ + 2H₂O

First, we calculate the moles of methane present using:
Moles = mass / molecular mass
Moles = 20 / 16
Moles = 1.25

Next, we may observe from the chemical equation that the molar ratio between methane and oxygen is 1 : 2
So the moles of oxygen required are 2 x 1.25
2.5 moles of oxygen required

Mass = moles * molecular mass
Mass = 2.5 * 32
Moles = 80

C. 80 grams O₂

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