Aballoon that had a volume of 3.50 l at 25.0°c is placed in a hot room at 40.0°c. if the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room? use mc005-1.jpg.

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 313.15 x 3.50 / 298.15

V2 = 3.68 L

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