A8.2 l sample of gas has a pressure of 0.8 atm at a temperature of 259 k. if the temperature increases to 301 k, causing the volume to increase to 11.5 l, what is the new pressure? round your answer to the nearest tenth

0.7 atm

Explanation:

For the Clapeyron's equation, we can calculate the change in the physical properties that happens when there is a state change:

P1*V1/T1 = P2*V2/T2

Where P is the pressure, V is the volume, T is the temperature, 1 is the initial state, and 2 the final state. So:

0.8*8.2/259 = P2*11.5/301

0.02533 = 0.038206*P2

P2 = 0.7 atm

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