Bf3 + li2so3 > b2(so3)3 + lif what is the coefficient of lithium fluoride in the balanced chemical reaction?
1
3
4
6

Ans) 6

The given equation is:

BF3 + Li2SO3 → B2(SO3)3 + LiF

# atoms in Reactants                                    # atoms in Products

B = 1                                                                   B = 2

F = 3                                                                   F = 1

Li = 2                                                                  Li = 1

S = 1                                                                    S = 3

O = 3                                                                   O = 9

In order to balance the unequal distribution of atoms, multiply BF3 by 2,  Li2SO3 by 3 and LiF by 6 to get:

2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF

Coefficient of LiF = 6

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

the awnser is group 12