When the [h+] in a solution is 1.7 × 10−9 m, what is the poh ?

[H⁺] = 1,7×10⁻⁹  mol/dm³

pH = -log[H⁺]
pH = -log[1,7×10⁻⁹]
pH = 8,77

pH + pOH = 14
pOH = 14-8,77
pOH = 5,23

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1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)