How many grams of sodium chloride are present in a 0.75 m solution with a volume of 500.0 mililiters

C = 0,75 mol/dm³
V = 500mL = 500cm³ = 0,5dm³

C = n/V
n = 0,75×0,5dm³
n = 0,375 moles

M NaCl:  23+35,5 = 58,5g

1 mole 58,5g
0,375 X
X = 0,375×58,5
X = 21,9375g NaCl

:)

This is what i found on google “when one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and atp is converted to adenosine diphosphate (adp). likewise, energy is also released when a phosphate is removed from adp to form adenosine monophosphate (amp).” i hope this you .

Ais your answer to this