Chemistry, 20.11.2019 00:31 leonardoocampo7555

What is the concentration of the base (lioh) in this titration?

a.) 1.20 m
b.) 1.18 m
c.) 30 m
d.) 1.5 m

What is the concentration of the base (lioh) in this titration? a.) 1.20 m b.) 1

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Answer from: dugg5361

If the conc. of HCl is 1.5 M, then 1000ml of HCl contain 1.5 mol
let 20ml of HCl (used in titration)contain x

⇒ x = (20 ml × 1.5 mol) ÷1000ml
x = 0.03 mol
∴ moles of HCl used to dissolve the LiOH was 0.03 mol

The reaction is characterised by the equation: HCl + LiOH → LiCl + H₂O

Based on the equation, the mole ratio of HCl : LiOH is 1 : 1
∴ if moles of HCl reacting = 0.03 mol
then moles of LiOH = 0.03mol

Now, since 25ml of LiOH reacted with the HCl,
then it implies that 25ml of LiOH contain 0.03 mol

∴ Let 25ml of LiOH contain 0.03mol
and 1000ml of LiOH contain y

⇒ y = (1000 ml × 0.03 mol) ÷ 25ml
y = 1.2 mol

∴ the concentration of the base (LiOH) in this titration is 1.2 M (OPTION A)

What is the concentration of the base (lioh) in this titration? a.) 1.20 m b.) 1.18 m c.) 30 m d.)

What is the concentration of the base (lioh) in this titration? a.) 1.20 m b.) 1.18 m c.) 30 m d.)

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

All the elements are arranged by melting points on the periodic table. in row they go from metals to gasses. in the row from sodium to argon, sodium is more reactive than the one on its right, magnesium.

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