The following balanced equation shows the formation of ammonia. n2 + 3h2 mc0

2nh3 how many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen? 1.02 mol 2.11 mol 12.68 mol 19.02 mol

                                     N₂   +   3H₂    →    2NH₃

Based on the reaction, Mole ratio of H₂  to  N₂   is   3  :  1  [ 1N₂ + 3H₂  → 2NH₃]

∴ if moles of Hydrogen = 6.34 mol 
then moles of nitogen = 6.34 mol ÷ 3
                                    = 2.11 moles

∴ 2.11 moles (OPTION 2) of Nitrogen is needed to convert 6.34 moles of Hydrogen into ammonia. 

2.11 mol or letter B if I am not mistaken 

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