How many moles of o2 are needed to react with 1.44 mol of aluminum(al)?
show work

Aluminum reacts with oxygen based on the following equation:
 4Al + 3O2 → 2Al2O3

From this balanced equation, we can see that 4 moles of aluminum are required to react with 3 moles of oxygen.

So, to find the number of moles of oxygen needed to react with 1.44 moles of aluminum, all you have to do is cross multiplication as follows:
required moles of oxygen = (1.44x3) / 4 = 1.08 moles

Ch4 and ph3 are both covalent since they are composed both of non-metals.    ch4 is non- polar because of  london forces and has a geometry of tetrahedral  ph3 , on the other hand, is umbrella shaped polar and has dipole-dipole intermolecular force (imf) . since ph3 is polar, it has a stronger imf